Please help Q 4 A short bar magnet placed in a horizontal plane has its axis - Physics - Magnetism And Matter

Question

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Q 4 A short bar magnet placed in a horizontal
plane has its axis aligned along the magnetic north-south direction
Null points are found on the axis of the magnet at 14 cm from the
centre of the magnet The earth's magnetic field at the place is 0
36 G and the angle of dip is zero What is the total magnetic field
on the normal bisector of the magnet at the same distance as the
null-points (i e , 14 cm) from the centre of the magnet ?

Sanjay Singh · Accepted Answer

Dear student
As angle of dip is the angle between the resultant magnetic field and the horizontal component of the magnetic field so in this case the angle is zero meansthe vertical component of the magnetic field is zero
Horizontal component BH=Bnet=0
3×10-4 TMagnetic field at the axial point is B=μ4π2Mr3At the neutral point μ4π2Mr3=0
3×10-4
1At the perpenducular bisector of the magnet B1=μ4πMr3 ( in the direction north to south )And magnetic field of the earth is =0
3×10-4 (in the direction north to south)Net magnetic field Bnet=0
3×10-4+μ4πMr3Bnet=0 3×10-4+0
3×10-42=3×0 3×10-42=1 5×0 3×10-4=0
45×10-4 TRegard