please solve question 15 Share with your friends Share 0 Shobhit Mittal answered this take a dx width ring at depth xpressure at this point be =ρghupward force dF=ρgh2πx.dx.cosθtheta is cone angle cosθ=hh2+R2\F=∫0hρgh2πxhh2+R2.dx=2πρgh2h2+R2h22=πρgh4h2+R2 upward forceRegards -1 View Full Answer