PLEASE VERY URGENT

3 moles of a mixture of FeSO4 and Fe2( SO4)3 required 100 ml of 2 molar (M) KMnO4 solution in acidic medium. hence mole fraction of FeSO4 in the mixture is

Question

PLEASE VERY URGENT
3 moles of a mixture of FeSO4 and Fe2( SO4)3 required 100 ml of
2 molar (M) KMnO4 solution in acidic medium hence mole fraction of
FeSO4 in the mixture is

Vartika Jain · Accepted Answer

Dear Student,

Here, FeSO4 has Fe in +2 oxidation state and Fe2(SO4)3 has Fe in +3 state
 So, KMnO4 will oxidise only Fe2+to Fe3+Therefore, the reaction occuring is2KMnO4 + 8H2SO4 +10FeSO4 → K2SO4 + 2MnSO4 + 5Fe2(SO4)3 + 8H2OEquivalents of FeSO4 = Equivalents of KMnO4or, Equivalents of FeSO4 = 0
1L × (2×5) N        (Since Normality=Molarity×n-factor and for KMnO4 in acidic medium, n=5)Therefore, Equivalents of FeSO4 = 1or, Moles of FeSO4 =Equivalentsn-factor=11            (Since for FeSO4 n=1)Therefore, Mole fraction of FeSO4 in the mixture=Moles of FeSO4Moles of mixture                                                                                     =13

PLEASE VERY URGENT 3 moles of a mixture of FeSO4 and Fe2( SO4)3 required 100 ml of 2 molar (M) KMnO4 solution in acidic medium. hence mole fraction of FeSO4 in the mixture is

PLEASE VERY URGENT

3 moles of a mixture of FeSO4 and Fe2( SO4)3 required 100 ml of 2 molar (M) KMnO4 solution in acidic medium. hence mole fraction of FeSO4 in the mixture is