Pls explain this .
Dear student
When alkali metals are dissolved in liquid ammonia, the alkali metal atom readily loses the valence electron. Both the cation and the electron combine with ammonia to form ammoniated cation and ammoniated electron.
M + (x+y)NH3 → [M(NH3)x]+ + [e(NH3)y]-
The ammoniated electron absorbs energy in the visible region of light and thus gives a blue colour to the solution. The solution is paramagnetic in nature and liberates hydrogen to form amide.
Please refer to the similar link for second part:
https://www.meritnation.com/ask-answer/question/trend-in-melting-and-boiling-point-fluoride-chloride/the-s-block-elements/3313443
Regards
When alkali metals are dissolved in liquid ammonia, the alkali metal atom readily loses the valence electron. Both the cation and the electron combine with ammonia to form ammoniated cation and ammoniated electron.
M + (x+y)NH3 → [M(NH3)x]+ + [e(NH3)y]-
The ammoniated electron absorbs energy in the visible region of light and thus gives a blue colour to the solution. The solution is paramagnetic in nature and liberates hydrogen to form amide.
Please refer to the similar link for second part:
https://www.meritnation.com/ask-answer/question/trend-in-melting-and-boiling-point-fluoride-chloride/the-s-block-elements/3313443
Regards