Pls solve 2nd question

Pls solve 2nd question 1/4 0/ its molecular weight. '9ht. ent. the we•qht Of KHC.O. H.C*Oa.2H20 iS (B) half Of Its molecular wetght. 2. A bottle, Which contains 200 (O) lf8 of its molecular wetqht. solution is then treated With ml Of 0M M KOH, absorbs 1 mittirnole of C02 frotn the air. If the (A) 0.095 N (C) 0.2 N Standard acid using phenolphthatetn Indicator. the norrnaüty (D) 0.036 N O. 126 g of an acid requires 20 ml of 0.1 N NaOH for complete neutralization. Equivalent weight of the acid is

200 m l o f 0.1 M K O H = 200 \times 0.1 = 20 m i l l i m o l e C O_{2} = 1 m i l l i m o l e K O H + C O_{2} \to K H C O_{3} T h e u n r e a c t e d b a s e h a s m i l l i e q u i v a l e n t a s = 20 ~ 1 = 19 m i l l i m o l e M o l a r i t y o f t h e a c i d = \frac{19}{200} = 0.095 M N o r m a l i t y o f t h e a c i d = 0.095 N

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