The normality of HCl = N1Normality of H2SO4 = N2Milliequivalent of HCl + Milliequivalent of H2SO4 = Milliequivalent of NaOH25 × N1 + 25 × N2 = 10 × 1 N1 +N2 =1025= 0 4 Moles of Cl = Moles of AgCl20×N11000 = 0 1435143 05= 10-3N1 =0 05 NN2 =0 35 N Thus option b is correct

Pls solve 8 question

Pls solve 8 question 0 -Z

T h e n o r m a l i t y o f H C l = N_{1} N o r m a l i t y o f H_{2} S O_{4} = N_{2} M i l l i e q u i v a l e n t o f H C l + M i l l i e q u i v a l e n t o f H_{2} S O_{4} = M i l l i e q u i v a l e n t o f N a O H 25 \times N_{1} + 25 \times N_{2} = 10 \times 1 N_{1} + N_{2} = \frac{10}{25} = 0.4 M o l e s o f C l = M o l e s o f A g C l \frac{20 \times N_{1}}{1000} = \frac{0.1435}{143.05} = 10^{- 3} N_{1} = 0.05 N N_{2} = 0.35 N

Thus option b is correct

View Full Answer

Pls solve 8 question Pls solve 8 question 0 -Z

Pls solve 8 question

Pls solve 8 question 0 -Z