PQ and RS are two parallel chords of a circle whose centre is O and radius 10 cm. If PQ=16cm, RS=12cm find the distane between PQ and RS if they lie.

Given that: PQ = 16 cm and RS = 12 cm are two parallel chords and radius of circle OS = OQ = 10 cm.

Let OM = x cm and ON = y cm

Since, perpendicular from the centre of the circle to a chord bisects the chord. So,

,

Similarly,

In, using Pythagoras Theorem

Similarly,

In, using Pythagoras Theorem

Therefore,

Distance between PQ and RS = OM + ON = x + y = 6 + 8 = 14 cm

Hence, distance between PQ and RS is 14 cm