Prove that sinA.sin(A+B) is equal to sin^2A.cosB+1/2 sin2A.sinB Share with your friends Share 6 Ahmad answered this solution -6 View Full Answer Avani answered this Remember Sin2A = 2sinAcosA So 1/2(sin2A) = sinAcosA Sin(A+B) = sinA.cosB+sinB.cosA Proof L. H. S = sinA(sinAcosB+ SinBcosA) =sinA^2cosB + *sinAcosA*sinB =sinA^2cosB+ 1/2(sin2A)sinB =RHS 4
