PROVE THAT THE AREA OF THE SEMI CIRCLE DRAWN ON THE HYPOENUSE OF A RIGHT ANGLED TRIANGLE IS EQUAL TO THE SUM OF THE AREAS OF THE SEMICIRCLES DRAWN ON THE OTHER TWO SIDES OF THE TRIANGLE.
Here is the proof.
Let ΔABC be right angled at B.
Let AB = c, BC = a, AC = b.
To prove:
Area of semi circle along AC = Area of semi circle along AB + Area of semi circle along BC
![](https://s3mn.mnimgs.com/img/shared/userimages/mn_images/image/CCs(1).png)
This proves the said result.
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