Login

prove that

cos [ 90 - A] / 1+ sin [90 - A] + {1+ sin [90- A]} / {cos [90- A] = 2cosecA

$Given \frac{\cos (90 - A)}{1 + \sin (90 - A)} + \frac{1 + \sin (90 - A)}{\cos (90 - A)} \Rightarrow \frac{\sin A}{1 + \cos A} + \frac{1 + \cos A}{\sin A} (∵ \cos (90 - A) = \sin A and \sin (90 - A) = \cos A) \Rightarrow \frac{\sin^{2} A + (1 + \cos A)^{2}}{\sin A (1 + \cos A)} \Rightarrow \frac{\sin^{2} A + 1 + \cos^{2} A + 2 \cos A}{\sin A (1 + \cos A)} \Rightarrow \frac{2 + 2 \cos A}{\sin A (1 + \cos A)} \Rightarrow \frac{2 (1 + \cos A)}{\sin A (1 + \cos A)} \Rightarrow \frac{2}{\sin A} \Rightarrow 2 \cos ecA$

8

View Full Answer

Copyright © 2024 Aakash EduTech Pvt. Ltd. All rights reserved.

Aakash EduTech Pvt. Ltd.

What are you looking for?