Q.33. The wavelength of the first line of Balmer series of hydrogen atom is $\lambda$. The wavelength of the same line in doubly ionised lithium will be
(a) $\frac{\lambda }{2}$
(b) $\frac{\lambda }{9}$
(c) $\frac{\lambda }{8}$
(d) $\frac{\lambda }{27}$