Q.8. Two coins are tossed. Find the probability of getting two heads when it is known that one Head has already occurred.

Hi Tarul dear, even A is getting two cards as black
Now 2 cards can be drawn from 52 in 52 C ₂ ways. That is 52 * 51/ 1 * 2 = 26 * 51
n(S) = 26 * 51
There are just half black cards. So 2 out of 26 can be drawn in 26 C₂ ways. That is 26 * 25 / 1 *2 = 13 * 25
So n(A) = 13 * 25
Thus P(A) = n(A)/n(S) = 13 * 25 / 26 * 51 = 25 / 102 = 0.245