Q A parallel-plate capacitor with plate area A and separation between the plates d is charged by a constant - Physics - Electromagnetic Waves

Question

Q A parallel-plate capacitor with plate area A and separation
between the plates d is charged by a constant current I Consider a
plane surface of area A/2 parallel to the plates and drawn
symmetrically between the plates Find the displacement current
through this area

Decoder_2 · Accepted Answer

Dear Student,If q be the charge on the capacitor at time t1, then electric field between plates of the capacitor is given by,E=q∈oANow we will find the flux through the plate which inbetween the two plates,so, flux through the area will be,ϕE=q∈oAA2=q2∈oDisplacement current ID = ∈odϕEdt=∈oddtq2∈o=I2(since dqdt=current)Regards

Q. A parallel-plate capacitor with plate area A and separation between the plates d is charged by a constant current I.Consider a plane surface of area A/2 parallel to the plates and drawn symmetrically between the plates. Find the displacement current through this area.