Q. A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from P to Q is ($\angle POQ =40°$ )

 

Dear student, 

It is given that the particle is moving in the circle with a uniform velocity v. As such the magnitude of velocity remains the same but the direction changes. We know the direction of velocity of a particle moving in a circle is along the tangent of that point. Since OP and OQ are at 40° with each other, their velocity vectors at P and Q will also be at the same angle to each other.

Hence,