Q21
Q21. The friction coefficient between the board and the floor shown in figure (6-E7 ) is . Find the maximum force that the man can exert on the rope so that the board does not slip on the floor.
Dear student,
Let T be the maximum force exerted by the man on the rope.
From the free body diagram,
R + T = Mg
⇒ R = Mg − T (1)
Again,
R1 − R − mg = 0
⇒ R1 = R + mg (2)
and
T − μR1 = 0
From Equation (2),
T − μ(R + mg) = 0
⇒ T − μR − μ mg = 0
⇒ T − μ(Mg − T) − μmg = 0
T − μMg + μt − μmg = 0
⇒ T (1 + μ) = μMg + μmg
Therefore, the maximum force exerted by the man is .
Regards