Q6) ii Q6) ii 11:53 o. 00K/s t 4G VoLTE Sayalee Ambulkar 1 day Iii,i oaaa Share with your friends Share 0 Sandeep Saurav answered this Dear Student, Given : y=tan-1(5x+13-x-6x2)To Find :dydx solution : y=tan-1(5x-13-x-6x2)applying ddx both the sides⇒ddx(y)=ddx{tan-1(5x-13-x-6x2)}⇒dydx=d{tan-1(5x-13-x-6x2)}d(5x-13-x-6x2)×d(5x-13-x-6x2)dx [using Chain Rule]⇒dydx=11+(5x-13-x-6x2)2×(3-x-6x2)(5-0)-(5x-1)(-1-12x)(3-x-6x2)2 ⇒dydx=1(3-x-6x2)2+(5x-1)(3-x-6x2)2×5(3-x-6x2)2+5x+60x2-1-12x(3-x-6x2)2⇒dydx=(3-x-6x2)2(3-x-6x2)2+(5x-1)×5(9+x2+36x4-6x+12x3-36x2)+60x2-7x-1(3-x-6x2)2⇒dydx=45-175x2+180x4-30x+60x3+60x2-7x-1(9+x2+36x4-6x+12x3-36x2)+(5x-1)⇒dydx=180x4+60x3-115x2-37x+4436x4+12x3-35x2-x+8 Hope this information will clear your doubts about topic. If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible. Keep posting!! Regards 0 View Full Answer Mridul Chandrawanshi answered this Please find this answer 0