Let E be the event that selected student reads Hindi newspaper Let F be the event that selected student reads English newspaper Now, PE = 60100 = 35 ⇒PE = 1 - 25 = 35Now, PF = 40100 = 25 ⇒ PF = 1 - 15 = 45Now, PE∩F = 20100 = 15Now, PE∪F = PE + PF - PE∩F=35 + 25 - 15=45Now, PE∪F = 1 - 45 = 15Now, a PE∩F = PE∪F = 15b PF/E = PE∩FPE = 1/53/5 = 13c PE/F = PE∩FPF = 1/52/5 = 12

Q8

Let E be the event that selected student reads Hindi newspaper . Let F be the event that selected student reads English newspaper . Now, P (E) = \frac{60}{100} = \frac{3}{5} \Rightarrow P (E) = 1 - \frac{2}{5} = \frac{3}{5} Now, P (F) = \frac{40}{100} = \frac{2}{5} \Rightarrow P (F) = 1 - \frac{1}{5} = \frac{4}{5} Now, P (E \cap F) = \frac{20}{100} = \frac{1}{5} Now, P (E \cup F) = P (E) + P (F) - P (E \cap F) = \frac{3}{5} + \frac{2}{5} - \frac{1}{5} = \frac{4}{5} Now, P (E \cup F) = 1 - \frac{4}{5} = \frac{1}{5} Now, (a) . P (E \cap F) = P (E \cup F) = \frac{1}{5} (b) . P (F / E) = \frac{P (E \cap F)}{P (E)} = \frac{1 / 5}{3 / 5} = \frac{1}{3} (c) . P (E / F) = \frac{P (E \cap F)}{P (F)} = \frac{1 / 5}{2 / 5} = \frac{1}{2}

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