s Q9 A bar magnet with poles 25 cm apart and of polc strength 14 4 Am rests - Physics - Magnetism And Matter

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Q9 A bar magnet with poles 25 cm apart and of polc strength 14 4 Am
rests with its centre on a frictionless pivot It is held in
equilibrium at 60° to a uniform magnetic field of induction 0
25 T by applying a force F at right angles to its axis, 12 cm from
its pivot Calculate F What will happen if the force F is removed?

Shobhit Mittal · Accepted Answer

dipole momentM=0 25*14 4=3
6  Am2torque by field T=M×B=3 6*0
25*sin60this torque is balance by force Ftorque by force T=F*0
12sin30F*0 12sin30=3 6*0 25*sin600 12F=3 6*0
253F=13 N if force is removed the magnet will allign with magnetic field of earthRegards