Dear student ,
Your answer is given below :-
sinϴxcosϴ=cosϴ ---(1)
Sinϴ = cosϴ/cosϴ
sinϴ=1
On putting this value in (1) , we get
1xcosϴ=cosϴ
cosϴ=cosϴ
L.H.S=R.H.S
Hence , proved.
Alternately ,
Sinϴxcosϴ=cosϴ
sinϴ=cosϴ/cosϴ
sinϴ=1
sinϴ=sin90
ϴ=90
so,
sin90xcos90=cos90
1x0=0 {As sin 90 = 1 and cos 90 = 0 }
0=0
L.H.S=R.H.S
Hence, proved.
Hope it helps :)
Thumbs up!