Solve 10 and 12: 10 . f ( x ) = x + 1 , i f x ≥ 1 x 2 + 1 , i f x < 1 12 . f ( x ) = x 10 - 1 , i f x ≤ 1 x 2 , i f x > 1 Share with your friends Share 0 Aarushi Mishra answered this Dear studentI am assuming that you are asking to check continuityFor fx to be continuous at x=a, limx→a+fx=limx→a-fx=fafx=x+1, if x≥1x2+1, if x<1f1=1+1=2limx→1+fx=limx→1+x+1 for x≥1, fx=x+1=1+1=2limx→1-fx=limx→1-x2+1 for x<1, fx=x2+1=12+1=2Thereforelimx→1-fx=limx→1+fx=f1=2Hence fx is continuousFor remaining queries please post them in a new thread 0 View Full Answer