Solve, Q ) 9 - 3 ÷ 1 3 + 1

Dear Student, 9-3÷13+1Using BODMAS, = 9-3×3+1= 9-9+1= 0+1= 1 Regards

Solve,
Q.) $9 - 3 \div \frac{1}{3} + 1$

Dear Student,

9 - 3 \div \frac{1}{3} + 1 U \sin g B O D M A S, = 9 - 3 \times 3 + 1 = 9 - 9 + 1 = 0 + 1 = 1

Regards

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