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Are the oxidation state and covalency of Al in [AlCl(H2O)3]2+ same . Give reasons also for the answer with explanation of how to find the oxidation state and covalency of an element in a compound.
Covalency is the number of surrounding ligands = 1 + 3 = 4
Oxidation state = x + (-1) + 3 x 0 = +2
x = +3
Thus the covalency of Al = 4 and oxidation state = +3
Oxidation state = x + (-1) + 3 x 0 = +2
x = +3
Thus the covalency of Al = 4 and oxidation state = +3