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Q.5.  A particle of mass m is placed at the centre of curvature of fixed, uniform semi-circular ring of radius R and mass M .  Calculate the interaction force between the ring and the particle.

Dear Student,
                      Here semicicular part will be symmetric in reference of centerwe can divide it in to two part , which making 900 each at center let a small mass element of ring in both the symmetric partat angle θ from vertical in both the side so dF=2GmdmR2cos(θ)here dm=MπR×Rdθ=MπF=2GmMπR2090cos(θ)dθ=2GmMπR2
Regards

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