Solve this: Q.5. A particle of mass m is placed at the centre of curvature of fixed, uniform semi-circular ring of radius R and mass M . Calculate the interaction force between the ring and the particle. Share with your friends Share 0 Vijay Shankar Yadav answered this Dear Student, Here semicicular part will be symmetric in reference of centerwe can divide it in to two part , which making 900 each at center let a small mass element of ring in both the symmetric partat angle θ from vertical in both the side so dF=2GmdmR2cos(θ)here dm=MπR×Rdθ=MπF=2GmMπR2∫090cos(θ)dθ=2GmMπR2 Regards -2 View Full Answer