Solve this.
Q). The de Broglie wavelength of an electron accelerated to a potential of 400 V is approximately
- 0.03 nm
- 0.04 nm
- 0.12 nm
- 0.06 nm
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Refer to the link below for the answer to a similar query,
https://www.meritnation.com/ask-answer/question/calculate-the-a-momentum-and-b-de-broglie-wavel/dual-nature-of-radiation-and-matter/6304971
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