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2Dear Student
Solution to your query 7 (the second option in the question) is given below.
7) Electronic configuration of Si (ground state)= 1s22s22p2
Electronic configuration of Si (excited state)= 1s22s12p3
Thus, there are 4 unpaired electrons which form four bonds with 4 electrons of 4 hydrogen.
Bond pair = 4, lone pair = 0, steric no. = 4 + 0 =4. Therefore geometry is tetrahedral and since no lone pair so no repulsion and the shape is same as geometry i.e. tetrahedral with 109.4o bond angle.
For remaining queries we request you to post them in separate threads to have rapid assistance from our experts.
Solution to your query 7 (the second option in the question) is given below.
7) Electronic configuration of Si (ground state)= 1s22s22p2
Electronic configuration of Si (excited state)= 1s22s12p3
Thus, there are 4 unpaired electrons which form four bonds with 4 electrons of 4 hydrogen.
Bond pair = 4, lone pair = 0, steric no. = 4 + 0 =4. Therefore geometry is tetrahedral and since no lone pair so no repulsion and the shape is same as geometry i.e. tetrahedral with 109.4o bond angle.
For remaining queries we request you to post them in separate threads to have rapid assistance from our experts.