Dear Student, Here in this case from the given data we can write that , kinetic energy=E=hcλ-W0=6·63×10-34×3×108300×10-9×1·6×10-19-1·55=2·59 eV Regards

solve:

solve: The work function of a metal is 1.55 eV. A photon of waveength 300 nm strikes metal surface. Calculatf the kinetic energy of the photoelectron. (1 eV — 1.6 x 10-19 J, h 6.63 x 10-34 Js)

Dear Student,
Here in this case from the given data we can write that ,

k i n e t i c e n e r g y = E = \frac{h c}{λ} - W_{0} = \frac{6 \cdot 63 \times 10^{- 34} \times 3 \times 10^{8}}{300 \times 10^{- 9} \times 1 \cdot 6 \times 10^{- 19}} - 1 \cdot 55 = 2 \cdot 59 e V

Regards

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solve: ​solve:​ The work function of a metal is 1.55 eV. A photon of waveength 300 nm strikes metal surface. Calculatf the kinetic energy of the photoelectron. (1 eV — 1.6 x 10-19 J, h 6.63 x 10-34 Js)

solve:

solve: The work function of a metal is 1.55 eV. A photon of waveength 300 nm strikes metal surface. Calculatf the kinetic energy of the photoelectron. (1 eV — 1.6 x 10-19 J, h 6.63 x 10-34 Js)