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the concentration of NO3 ions when equal volumes of 0.1 M AgNO3 and 0.1 M Nacl are mixed together is ?

0.1M AgNO3 contains 0.1 moles of Ag+ and 0.1 moles of NO3- ions in 1L of solution. It was mixed with 0.1M NaCl of equal volume.

Here the quantity of NO3- is same but the volume is doubled. So its concentration will be reduced to half. So the concentration of NO3- is 0.05M

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Here what u need***☜☆☞

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0.05 Mole is the answer. As , AgNo3 + NaCl ----------> AgCl + NaNo3 At t=0 0.1 0.1 0 0 Let volume of each be 1L. So For Agno3 given mole is 0.1 and conc. Of no3 is also 1. So conc. Of No3- = 0.1/2 = 0.05 Here 0.1 is mol of Agno3 contributing towards ionisation and 2 is the total volume of solution in which this reaction took place
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Here is the ans:-

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Simple 😇

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As the relation between conc and volume is inversly proportional , the conc remained constant the vol is reduced to half

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But the answer is 5m
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0.1?2=0.05
As the solution contains 2 litre.
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Please find this answer

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This is the answer

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Pi =n1i1+n2i2. Pi=cRT then 0.1*3+0.1*2=0.05
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Mokhtth
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Answer to this question

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Answer will be 0.1/2=0.05
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0.2 and 0.8
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Hope this helps you

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?????? ?? ????????
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Vapour pressure of pure water at 23?k is 19.8torr calculate the vapour pressure of 3m aqueous solution
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nidan number Arakkonam explain and Angela

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Army
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Maha
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O.04 mole
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0.05 is the answer
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Please find this answer

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22222
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Hope this helps

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