The denominator of a fraction exceeds the numerator by 3. The Sum of the fraction and it's multiplicative inverse is 65/28. Find the fraction

Let the numerator = xThen the denominator = x + 3Now, required fraction = xx+3Now, according to question :xx+3 + x+3x = 6528x2+x2+9+6xxx + 3 =  65282x2 + 6x + 9x2 + 3x = 652865x2 + 195x = 56x2 + 168x + 2529x2+ 27x - 252 = 0x2 + 3x - 28 = 0x2 + 7x - 4x - 28 = 0xx + 7 - 4x + 7 = 0x - 4x + 7 = 0x = 4   or   x = -7  rejectedSo, x = 4Now, required fraction = 47

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