The diameter of a capillary tube is 0.4 x 10-3 m. It is held vertically in a liquid whose density is 0.8 x 103kg m-3 and the surface tension is 9.8 x 10-2 N m-1. Determine the height to which the liquid will rise in the tube. Given, g = 9.8 m s-2 and angle of contact is zero

Height  of liquid column in a capillary is given by  h = 2Tcosθρgr 
 where T  surface  tension,  ρ  density of  liquid  
            g    acceleration due to gravity ,  r-  radius of capillary and  θ   angle of contact .
radius of capillary   r =D2 = 0.4×10-32  = 0.2×10-3m   h = 2×9.8×10-2×cos 000.8×103×9.8×0.2×10-3   h= 2×10-20.8×0.2  h = 12.5×10-2m                                    h= 12.5 cm      (ANS)

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