The radius of the earth is 6*10^9.at what distance from the centre of earth the weight of the body become half

Dear student,




$$\begin{gathered} h=(\sqrt{2}-1)\times 6\times {10}^{9}m \\ h=0.4\times 6\times {10}^{9}m \\ h=2.4\times 6\times {10}^{9}m \end{gathered}$$

As the acceleration due to gravity becomes half at this height, weight will also become half
Regards