The value of 0 . 16 log 2 . 5 1 3 + 1 3 2 + 1 3 3 + . . . to ∞ is (a) 0.16 (b) 1 (c) 0.4 (d) 4 Share with your friends Share 0 Brijendra Pal answered this Hi, Expression 13+132+133+....∞ is GP with a = 13 and r = 13213= 13so sum = a1-r= 131-13= 12= 0.5so 0.16log2.50.5= 0.16log0.520.5=0.1612log0.50.5=0.1612=0.4×0.4= 0.4 using property logxyr=1ylogxr -1 View Full Answer