Two particles A and B start from the same position along the same straight line. A goes with constant velocity 40m/s, whereas B stars from rest with constant acceleration 2ms-2. Then find the maximum distance between A and B before B overtakes A Share with your friends Share 0 Ved Prakash Lakhera answered this Let at time t the maximum distance between A and B =S1-S2Therefore S1-S2=40t-12×2×t2=40t-t2Now differentiating above eqn with respect to time we get dS1-S2dt=40-2tIn case is maximum then dS1-S2dt=0Therefore 40-2t=0or t=20sThus maximum distance between A and B is S1-S2=40×20-20×20=800-400=400m -1 View Full Answer