Using electron transfer concept identiofy the oxidant and reductant min both the cases plsspls in notebook eexplain nicely too Solve b) and c) only Share with your friends Share 0 Geetha answered this I will show how to find out the oxidant and reductant by taking some exampleSimilar to the one you try the rest. a) Zn + 2 H+ →Zn2+ + H2Here the oxidation number of Zn (0) changes to Zn2+(+2). Increase in oxidation number is oxidation. That means Zn acts as reductant (reducing agent)Here the oxidation number of H+(+1) changes to H2(0). Decrease in oxidation number is reduction. That means H+ acts as oxidant (oxidising agent)d) BrO3 -+ F2 + 2 OH- →BrO4- +2F-+ H2OHere the oxidation number of Br in BrO3 -(+5) changes to Br in BrO4-(+7). Increase in oxidation number is oxidation. That means BrO3 - acts as reductant (reducing agent)Here the oxidation number of F2(0) changes to F-(-1). Decrease in oxidation number is reduction. That means F2 acts as oxidant (oxidising agent) -1 View Full Answer
