What could be.the positon of element with atomic no 44. Plz urgent i hv to complete my assignment

Dear Student,

Electronic configuration of element with atomic number 44 is [Kr] 4d7 5s1Total number of valence electrons =7+1=8So, group number is 8. The element belong to d-block elementsThe element belong to period 5 as 5 shells are present. 

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  1. First take the Atomic number of the given element. Say Cl... Atomic no. 17
  2.       Then calculate the electronic configuration using the atomic number 2+8+7=17 therefore the electronic configuration will be 2, 8, 7.
  3.     Here we find that the no of valence electrons of element is 7 as the valence shell has 7 electrons.
  4.   So know we easily understand that the group is 7 because the no of valence electrons is 7.
  5.    Now to find the period we have to understand that the period is the number of shell the element is having therefore here chlorine has 3 shells (K-2, L-8, and M-7). So the period of the given element is 3.
  6.  
 Now for your question:
2,8,8,18,8. 
this element has a d-block, so according the the extended periodic table, it will be in group 8 (transition element), and 5 shells, therefore period 5.
Ruthenium 
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